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Exam Code: MCAT
Exam Questions: 815
Medical College Admission Test: Verbal Reasoning, Biological Sciences, Physical Sciences, Writing Sample
Updated: 04 Jan, 2026
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Question 1

Compounds containing a hydroxyl group attached to a benzene ring are called phenols. Derivatives of phenols,
such as naphthols and phenanthrols, have chemical properties similar to those of phenols, as do most of the
many naturally-occurring substituted phenols. Like other alcohols, phenols have higher boiling points than
hydrocarbons of similar molecular weight. Like carboxylic acids, phenols are more acidic than their alcohol
counterparts. Phenols undergo a number of different reactions; both their hydroxyl groups and their benzene
rings are highly reactive. A number of chemical tests can be used to distinguish phenols from alcohols and
carboxylic acids.
MCAT-part-3-page300-image70
Thymol, a naturally occurring phenol, is an effective disinfectant that is obtained from thyme oil. Thymol can
also be synthesized from m-cresol, as shown in Reaction A below. Thymol can then be converted to menthol,
another naturally-occurring organic compound; this conversion is shown in Reaction B.
Reaction A
MCAT-part-3-page300-image69
Reaction B
MCAT-part-3-page300-image68
Comparing the Ka values for cyclohexanol (Ka = 10−13) and phenol (Ka = 1.3 × 10−10) reveals that phenol is more
acidic than cyclohexanol. Which of the following explain(s) the acidity of phenol?
I. The exceptionally strong hydrogen bonding possible with phenol facilitates the loss of a proton, making it
more acidic than cyclohexanol.
II. Phenol’s conjugate base, phenoxide, is stabilized by resonance to a greater extent than phenol itself.
III. The negative charge of the oxygen atom on the phenoxide ion is delocalized over the benzene ring.

Section: Biological Sciences 

Options :
Answer: C

Question 2

Yeast can be used to covert simple sugars into:

Section: Physical Sciences 

Options :
Answer: C

Question 3

Nitric oxide, NO, has recently been found to have widespread physiological effects, acting as a major regulator
in the nervous, cardiovascular, and immune systems. The production of NO in the body is regulated by specific
NOS enzymes which exist in at least three different isoforms – bNOS, eNOS, and macNOS. Each of these
isoforms differ in location and function and serve to mediate different physiological responses to NO. Some
physiological roles of NO have been demonstrated as follows:
I. In the central nervous system, NO production is regulated by bNOS. Calcium ion concentrations of 200-400
nM in the central nervous system activate bNOS to catalyze the formation of NO. NO exerts definite effects on
brain function although its specific roles are not well established. bNOS inhibitors have been found to block the
release of neurotransmitter from presynaptic neurons. Excess levels of NO are also thought to contribute to
neurodegenerative disorders such as Alzheimer’s disease.
II. In the blood vessels, NO is produced by eNOS which is activated by Ca2+ concentrations of 200-400 nM. NO
acts as the major endogenous vasodilator in blood vessels. It diffuses into smooth muscle cells and leads to
muscle relaxation by stimulating cGMP formation through activation of guanylyl cyclase. In addition, NO
regulates the vascular system by inhibiting platelet aggregation and adhesion.
III. The role of NO in the immune system is regulated by macNOS through a pathway that is not Ca2+
dependent. Rather, exposure to cytokines, including interleukin-1 and interferon- γ, leads to synthesis of large
amounts of NO by activation of macNOS in response to inflammatory stimuli. The NO produced plays a
definitive role in the mediation of the activities of macrophages and neutrophils. NO also acts to inhibit the
mechanism of viral replication.
A “knock out” mouse with a mutant bNOS protein was generated by recombination techniques. The mutant
protein was identical to the wild-type protein except for the identity of amino acid 675; the mutated bNOS has
Tryptophan instead of Cysteine at position 675. Which of the following is responsible for the mutant protein?

Section: Biological Sciences 

Options :
Answer: C

Question 4

The equation of state of an ideal gas is given by the ideal gas law: PV = nRT where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas. The gas particles in a container are constantly moving at various speeds. These speeds are characterized by the Maxwell shown in the figure below.

MCAT-part-1-page303-image25
If two particles collide, their velocities change. However, if the gas is in thermal equilibrium, the velocity
distribution of the gas as a whole will remain unchanged by the collision.
The average kinetic energy (E) of a gas particle is given by:
MCAT-part-1-page303-image24
Equation 1
where m is the mass of one particle and u is the root mean square speed (rms speed) of the gas particles:
MCAT-part-1-page303-image23
where N is the number of gas particles; this is different from the average speed. For an ideal gas, the kinetic
energy of all the particles is:
MCAT-part-1-page303-image22
Equation 2
where n is the number of moles of gas. Combining these equations gives:
MCAT-part-1-page303-image21
Equation 3 where M is the molar mass of the gas particles. The average distance a particle travels between collisions is known as the mean free path l. Intuitively, the mean free path (mfp) could be expected to be larger for gases at low pressure, since there is a lot of space between particles. Similarly, the mfp should be larger when the gas particles are small. The following expression for the mfp shows this to be correct.
MCAT-part-1-page303-image30
Equation 4
In this equation, s is the atomic diameter (typically on the order of 10-8), k is the Boltzmann constant, and P is
the pressure.
In addition to colliding with one another, gas particles also collide with the walls of their container. If the
container wall has a pinhole that is small compared to the mfp of the gas, and a pressure differential exists
across the wall, the particles will effuse (or escape) through this pinhole without disturbing the Maxwellian
distribution of the particles. The rate of effusion can be described by:
MCAT-part-1-page303-image29
Equation 5
Where neff is the number of moles of effusing particles, A is the area of the pinhole, P and P1 are the pressures
on the inside and outside of the container wall respectively, and P > P1.
Which of the following will have the smallest root mean square speed at 298K?

Section: Physical Sciences 

Options :
Answer: A

Question 5

Band theory explains the conductivity of certain solids by stating that the atomic orbitals of the individual atoms
in the solid merge to produce a series of atomic orbitals comprising the entire solid. The closely-spaced energy
levels of the orbitals form bands. The band corresponding to the outermost occupied subshell of the original
atoms is called the valence band. If partially full, as in metals, it serves as a conduction band through which
electrons can move freely. If the valence band is full, then electrons must be raised to a higher band for
conduction to occur. The greater the band gap between the separate valence and conduction bands, the poorer
the material’s conductivity. Figure 1 shows the valence and conduction bands of a semiconductor, which is
intermediate in conductivity between conductors and insulators.
MCAT-part-1-page303-image150
Figure 1
When silicon, a semiconductor with tetrahedral covalent bonds, is heated, a few electrons escape into the
conduction band. Doping the silicon with a few phosphorus atoms provides unbonded electrons that escape
more easily, increasing conductivity. Doping with boron produces holes in the bonding structure, which may be
filled by movement of nearby electrons within the lattice. When a semiconductor in an electric circuit has
excess electrons on one side and holes on the other, electron flow occurs more easily from the side with
excess electrons to the side with holes than in the reverse direction.
MCAT-part-1-page303-image149
Figure 2
How does heat increase the conductivity of a semiconductor?
I) By reducing collisions between moving electrons
II) By breaking covalent bonds
III) By raising electrons to a higher energy level

Section: Physical Sciences 

Options :
Answer: D

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