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Consider the following Ruby code snippet that incorporates the use of refinements:

module StringAdjustments refine String do def emphasize "#{self}!" end endend class Writer using StringAdjustments  def emphasize_statement(statement) statement.emphasize endend writer = Writer.newexternal_statement = "Hello".emphasize result1 = writer.emphasize_statement("Hello")result2 = external_statement What will be the values of result1 and result2, respectively?

Review the following Ruby code snippet:

def divide_numbers(x, y) x / yrescue ZeroDivisionError => e puts "Error: #{e.message}"end result1 = divide_numbers(10, 2)result2 = divide_numbers(10, 0)result3 = begin divide_numbers(10, '5') rescue TypeError => e "Caught: #{e.class}" endresult4 = divide_numbers(10, nil) rescue "Invalid operation" What will be the values of result1, result2, result3, and result4, respectively?

In Ruby programming, the correct use and understanding of operators is essential. Analyze the following Ruby code snippet:

a = 8b = 4result1 = a != bresult2 = a & b == 4result3 = (a * 2) / b Based on this code, which two of the following statements are true regarding the use and precedence of the operators?

Analyze the following Ruby code snippet that utilizes regular expressions for string processing:

class EmailExtractor EMAIL_REGEX = /(\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b)/  def self.extract_from(text) text.scan(EMAIL_REGEX).flatten endend text1 = "Contact us at [email protected] for assistance"text2 = "Send your feedback to: [email protected] and [email protected]"text3 = "No emails here!" result1 = EmailExtractor.extract_from(text1)result2 = EmailExtractor.extract_from(text2)result3 = EmailExtractor.extract_from(text3) What will be the values of result1, result2, and result3, respectively?

Consider the following Ruby code snippet involving the implementation and usage of the Comparable module:

class TimeRange include Comparable  attr_reader :start_time, :end_time  def initialize(start_time, end_time) @start_time = start_time @end_time = end_time end  def (other) return nil unless other.is_a?(TimeRange) [start_time, end_time] [other.start_time, other.end_time] endend time_range1 = TimeRange.new(10, 20)time_range2 = TimeRange.new(15, 25)time_range3 = TimeRange.new(10, 20) result1 = time_range1 time_range3  What will be the values of result1, result2, and result3, respectively?